limx→0 sin⁡πcos2⁡xx2 is equal to

limx→0 sin⁡πcos2⁡xx2                    00 form⇒ lima→0 sin⁡π−πsin2⁡xx2⇒ limα→0 sin⁡πsin2⁡xπsin2⁡x×πsin⁡xx2=1×π(1)2=π