limx→π/6 3sinx−3cosx6x−π equals
3
13
−3
−13
We have,
limx→π/6 3sinx−3cosx6x−π=limx→π/6 2332sinx−12cosx6x−π6=limx→π/6 13sinx−π6x−π6=13
ALITER We have,
limx→π/6 3sinx−3cosx6x−π 00 form
=limx→π/6 3cosx+3sinx6 [Using De L Hospital's Rule]
=163cosπ6+3sinπ6=13