First slide
Introduction to limits
Question

limx0xloge(sinx) is equal to

Moderate
Solution

We have,

limx0xlogesinx                    [0× form ]

=limx0logesinx 1/x                 form 

=limx0cotx1/x2                    [Using L' Hospital's rule] 

=limx0x2tanx=limx0xtanx×x=(1×0)=0=loge1

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