limx→∞ x4sin1x+x21+|x|3 is
2
1
-1
does not exist
limx→∞ x4sin1x+x21+|x|3
LetL=limx→−∞ x31+|x|3xsin1x+1x
=limx→−∞ x3|x|311+1|x|xxsin1x+1x
now,
limx→−∞ x3|x|3=limx→−∞ x3−x3=−1[∵|x|=−x for x<0]limx→−∞ 1|x|x=0
and limx→−∞ xsin1x=limy→0− sinyy=1 where y=1x
From eq (i) L=−111+0(1+0)=−1