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Q.

limx→−∞x2sin1x4x2−x+1=

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a

12

b

-12

c

−13

d

13

answer is B.

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Detailed Solution

limx→-∞ x2sin1xx4-1x+1x2=limx→-∞ -sin1x1x   4-1x+1x2 (as x→-∞ x=-x)plug in x=1y  in the given limitlimy→0−sinyy4y2−1y+1=limy→0−1y2−y+4 limy→0sin y y=−14=−12
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