limx→3 [x]−3(x−3) is equal to

limx→3 [x]−3(x−3)Towards the right of r= 3, [r] = 3 [x] - 3 = 0, in the right neighborhood of x = 3⇒limx→3+0 [x]−3x−3=0Towards the left of x= 3, [x]=2 ⇒[x]−3=−1, in the left neighborhood of x =3⇒limx→3−0 [x]−3x−3=limx→3−0 −1x−3=∞Thus,limx→3 [x]−3(x−3) does not exist