limx→0 1+x+x2−exx2 is equal to
1
0
1/2
none of these
We have
limx→0 1+x+x2−xxx2=lim_x→01+x+x2−1+x+x22!+x33!+…x2=limx→0 1−12!−x3!−x24!+….=1−12=12