A line bisecting the ordinate PN of a point P (at2 , 2at), t > 0, on the parabola y2 = 4ax is drawn parallel to the axis to meet the curve at Q. If NQ meets the tangent at the vertex at the point T, then the coordinates of T are.
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a
(0,4at/3)
b
(0,2at)
c
at2/4,at
d
(0, at)
answer is A.
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Detailed Solution
Equation of the line parallel to the axis and bisecting the ordinate PN of the point P (at2 , 2at) is y =at which meets the parabola y2 = 4ax at the point Qat24,at Coordinates of N are (at2 , 0). Equation of NQ is y=0−atat2 at2/4x−at2which meets the tangent at the vertex, x = 0, at the point y = 4at/3.