A line is drawn through the point (1, 2) to meet the coordinate axes at P and Q such that it forms a triangle OPQ, where O in the origin. If the area of the triangle OPQ, is least, then the slope of the line PQ is
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a
-2
b
– 1/2
c
– 1/4
d
– 4
answer is A.
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Detailed Solution
Equation of the line be y=mx+cSince it passes through (1, 2), 2 = m + cP(0, c), Q(-c / m, 0) If A is the area of the triangle, thenA=12|c|cm=c22m=(2-m)22m=m2-4m+42m=m2-2+2mdAdm=0⇒12-2m2=⇒m2=4⇒m=±2