Q.
A line having direction ratios ⟨1,0,3⟩cuts planes x-y+6z=6 and x-y+6z=4 at P and Q then PQ.
see full answer
Start JEE / NEET / Foundation preparation at rupees 99/day !!
21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya
a
310
b
21019
c
10
d
31019
answer is B.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
Suppose that θ be the acute angle between the line whose direction ratios are ⟨1,0,3⟩ and the plane x-y+6z=6hence, sinθ=al+bm+cna2+b2+c2l2+m2+n2=1+181+91+1+36=191038and sinθ=PMPQ where PM is perpendicular distance from the point to the plane, or it is equal to the distance between two parallel planes. hence, PM=c2−c1a2+b2=21+1+36=238Therefore, PQ=PMsinθ=238103819=21019
Watch 3-min video & get full concept clarity