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Questions  

A line having direction ratios 1,0,3cuts  planes x-y+6z=6 and x-y+6z=4 at P and Q then PQ.

a
310
b
21019
c
10
d
31019

detailed solution

Correct option is B

Suppose that  θ be the acute angle between the line whose direction ratios are ⟨1,0,3⟩ and the plane x-y+6z=6hence,  sinθ=al+bm+cna2+b2+c2l2+m2+n2=1+181+91+1+36=191038and sinθ=PMPQ where PM is perpendicular distance from the point to the plane, or it is equal to the distance between two parallel planes. hence, PM=c2−c1a2+b2=21+1+36=238Therefore, PQ=PMsinθ=238103819=21019

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