A line having direction ratios ⟨3,4,5⟩ cuts two planes 2x−3y+6z−12=0 and  2x−3y+6z+2=0 at point P and at  point  Q then the length of PQ

If θ is acute angle between the line having direction ratios ⟨3,4,5⟩ and  the planes given, and the perpendicular distance PM from P to the plane  2x−3y+6z−12=0 then sinθ=PMPQHere it implies that sinθ=al+bm+cna2+b2+c2l2+m2+n2 and PM=ax1+by1+cz1+da2+b2+c23(2)+4(−3)+5(6)9+16+25⋅4+9+36=12+24+9+36PQ245049=2PQPQ=35212