Q.
A line having direction ratios ⟨3,4,5⟩ cuts two planes 2x−3y+6z−12=0 and 2x−3y+6z+2=0 at point P and at point Q then the length of PQ
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a
35212
b
35224
c
3526
d
3528
answer is A.
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Detailed Solution
If θ is acute angle between the line having direction ratios ⟨3,4,5⟩ and the planes given, and the perpendicular distance PM from P to the plane 2x−3y+6z−12=0 then sinθ=PMPQHere it implies that sinθ=al+bm+cna2+b2+c2l2+m2+n2 and PM=ax1+by1+cz1+da2+b2+c23(2)+4(−3)+5(6)9+16+25⋅4+9+36=12+24+9+36PQ245049=2PQPQ=35212
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