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A line having direction ratios 3,4,5 cuts two planes 2x3y+6z12=0 and  2x3y+6z+2=0 at point P and at  point  Q then the length of PQ

a
35212
b
35224
c
3526
d
3528

detailed solution

Correct option is A

If θ is acute angle between the line having direction ratios ⟨3,4,5⟩ and  the planes given, and the perpendicular distance PM from P to the plane  2x−3y+6z−12=0 then sinθ=PMPQHere it implies that sinθ=al+bm+cna2+b2+c2l2+m2+n2 and PM=ax1+by1+cz1+da2+b2+c23(2)+4(−3)+5(6)9+16+25⋅4+9+36=12+24+9+36PQ245049=2PQPQ=35212

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The equation to the plane through the line of intersection of 2x+y+3z2=0,xy+z+4=0 such that each plane is at a distance of 2 unit from the origin is


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