The line of intersection of the planes x-y+6z=0 and 2x+3y-z=5 is

To get a point on the line of intersection of given two planes, substitutez=0  in the equations Hence, x-y=0  and 2x+3y=5it gives, a point on the line of intersection of two planes as P(1,1,0)The direction ratios o the line is proportional to the vector ijk1−1623−1=i(−17)−j(−13)+k(5)Therefore, the equation of the line of intersection of two planes is x−1−17=y−113=z5