First slide
Equation of line in Straight lines
Question

The line joining A (bcosa, bsina) and B (a cosb, a sinb ) is produced to the point M (x, y) so that AM:MB=b:a,, then xcosα+β2+ ysinα+β2=

Moderate
Solution

As M divides AB externally in the ratio b : a
x=b(acosβ)a(bcosα)ba and 
          y=b(asinβ)a(bsinα)ba xy=cosβcosαsinβsinα=2sinα+β2sinαβ22cosα+β2sinβα2 xcosα+β2+ysinα+β2=0

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