The line L is given by  x5+yb=1  passes through the point (13, 32). The line K is parallel to L  and has the equation  xc+y3=1 Then the distance between L  and K  is

As L:x5+yb=1 passes through  (13,32), we get  135+32b=1⇒b=−20As   K:xc+y3=1   is parallel to  L−b5=−3c⇒c=−34Now equation of L and K are respectively 4x−y−20=0 and 4x−y+3=0and  the distance between them is|−20−3|16+1=2317