A line l  meets the circle x2+y2=61  in A and B and P(-5,6)  is such that PA=PB=10  the equation of l  is

P(−5,6)  lies on x2+y2=61→(1)PA=PB=10Equation of circle with centre P & radius 10 is x2+y2+10x−12y−39=0AB¯  is the radical axis of circle (1)&(2)⇒5x−6y+11=0