The line L1=4x+3y−12=0 intersects the x-and y-axis A and B, respectively. A variable line perpendicular to L1 intersects the x-and the y-axis at P and Q, respectively. Then the locus of the circumcentre of triangle ABQ is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
3x−4y+2=0
b
4x+3y+7=0
c
6x−8y+7=0
d
none of these
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Clearly, the circumcenter of triangle ABQ will lie on the perpendicular bisector of line AB. Now, the equations of perpendicular bisector of line AB is 3x−4y+7/2=0. Hence, the locus of circumcentre is 6x−8y+7=0