Q.
The line L1=4x+3y−12=0 intersects the x-and y-axis A and B, respectively. A variable line perpendicular to L1 intersects the x-and the y-axis at P and Q, respectively. Then the locus of the circumcentre of triangle ABQ is
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a
3x−4y+2=0
b
4x+3y+7=0
c
6x−8y+7=0
d
none of these
answer is C.
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Detailed Solution
Clearly, the circumcenter of triangle ABQ will lie on the perpendicular bisector of line AB. Now, the equations of perpendicular bisector of line AB is 3x−4y+7/2=0. Hence, the locus of circumcentre is 6x−8y+7=0
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