First slide

Equation of line in Straight lines

Question

The line $(p + 2 q) x + (p - 3 q) y = p - q$ .for different values of $p$ and $q$ passes through the fixed point

Moderate

A

(3/2,5/2)
B

(2/5,2/5)
C

(3/5, 3/5)
D

(2/5, 3/5)

Solution

We have,
$\begin{array}{l} (p + 2 q) x + (p - 3 q) y - p + q = 0 \\ \Rightarrow p (x + y - 1) + q (2 x - 3 y + 1) = 0 \end{array}$
Clearly, it represents a family of lines passing through the
intersection of the lines $x + y - 1 = 0$ and $2 x - 3 y + 1 = 0$ .
The coordinates of the point of intersection these two lines are
(2/5, 3/5).

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App