The line (p + 2q) x + (p – 3q)y = p – q for different values of p and q passes through the fixed point

The equation of the given line can be re-written as p(x + y – 1) + q(2x – 3y + 1) = 0 which, clearly, passes through the point of intersection of the linesx + y – 1 = 0 ------(1) and 2x – 3y + 1 = 0 -------(2)for different values of p and qSolving (1) and (2), we get the coordinates of the point of intersection as 25,35.