A line passing through P (6, 4) meets the coordinates axes at A and B respectively. If O is the origin, then locus of the centre of the circumcircle of triangle OAB is
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a
3x−1+y−1=1
b
x−1+2y−1=1
c
x−1+y−1=1
d
3x−1+2y−1=1
answer is D.
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Detailed Solution
Let mid point of AB=(x1,y1)=MA=(2x1,0),B(0,2y1)Equation of line AB is x2x1+y2y1=1,and it passes through (6, 4)⇒62x1+42y1=1⇒3x1+2y1=1Locus of M is 3x−1+2y−1=1