Q.
A line perpendicular to the line segment joining the points (7, 3) and (3, 7) divides it in the ratio 1:3, the equation of the line is
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a
x+y-10=0
b
x-y+4=0
c
x-y+2=0
d
x-y-2=0
answer is D.
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Detailed Solution
Slope of the given line is 7-33-7=-1 and the coordinates of the point which divides the given line segment in the ratio 1:3 is 1×3+3×74,1×7+3×34=(6,4)So equation of the line passing through the point (6, 4) and perpendicular to the given line isy−4=x−6 ⇒ x−y−2=0.
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