A line with direction ratios 2,1,2 intersect each of the lines x=y+a=z and x+a=2y=2z the co-ordinates of each of the points of intersection are
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a
3a,3a,3a,a,a,a
b
3a,2a,3a,a,a,a
c
3a,2a,3a,a,a,2a
d
2a,3a,2a,2a,a,a
answer is B.
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Detailed Solution
The given lines arex1=y+a1=z1, x+a2=y1=z1Suppose that the line L intersect the above two lines at P,QThe direction rations of PQ are 2,1,2The points Ps,s−a,sand Q2t−a,t,t, these are general points on the given two lines. Direction ratios of PQare 2t−a−s,t−s+a,t−s, these are proportional to 2,1,2It implies that 2t−a−s2=t−s+a1=t−s2Hence, s=3a,t=aTherefore, the points of intersections are P3a,2a,3a, Qa,a,a