A line with positive rational slope, passes through the point A6,0 and is at distance of 5 units from B1,3. The slope of line is

Equation of line through point A6,0 and having slope m is y−0=mx−6,m>0or mx−y−3m=0,   m>0                            ….(1)Distance of this line from point B1,3 is 5.So, m−3−6m1+m2=5⇒3+5m2=251+m2⇒9+30m=25⇒m=1630=815