The line xa−yb=1 cuts the x-axis at P. The equation of the line through P perpendicular to the given line, is

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x+y=ab

x+y=a+b

ax+by=a2

bx+ay=b2

answer is C.

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Detailed Solution

The line xa−yb=1 cuts x-axis at P(a,0). The equation of the line through P(a,0) and perpendicular to xa-yb=1, is y−0=−ab(x−a)⇒ax+by=a2

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