The line xa+yb=1 meets the x-axis at A, the y-axis  at B, and the line y=x at C such that the area of ΔAOC is twice the area of ΔBOC. Then the coordinates of C are

Given arΔAOC=2arΔBOCor 12OAx1=2×12OBx1or a=2bThe equation of AB is xa+yb=1     …(1) or x2b+yb=1  …(2)Since point C lies on line  (2),we have x12b+x1b=1or x1=2b3=a3or C≡2b3,2b3