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The line $3 x - 2 y = k$ meets the circle $x^{2} + y^{2} = 4 r^{2}$ at only one point, if $k^{2} =$

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Correct option is B

The line 3x - 2y - k = 0 meets the circle x2 + y2 = 4r2 at only one point. So, it is a tangent to the circle. ∴ 3×0−2×0−k32+(−2)2=2r⇒k2=52r2

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The line 3x-2y=k meets the circle x2 + y2 = 4r2 at only one point, if k2 =

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Ready to Test Your Skills?

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The line $3 x - 2 y = k$ meets the circle $x^{2} + y^{2} = 4 r^{2}$ at only one point, if $k^{2} =$