The line x3+y4=1meets the y and x-axis at A and B, respectively. A square ABCD is constructed on the line segment AB away from the origin. The coordinates of the vertex of the square farthest from the origin are
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a
(7,3)
b
(4,7)
c
(6,4)
d
(3, 8)
answer is B.
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Detailed Solution
The coordinates of A are (0, 4) and those of B are (3, 0). BC=AB=32+42=5In △BCL ∠CBL=180-90-θ=90-θsin(90-θ)=CLBCcos θ= CLBC and CL=BCcosθcos(90-θ)=BLBCor BL=BCsinθ or BL=5×45=4 and CL=5×35=3 Similarly, MD=4 and AM=3 . So, the coordinates of C are (OB+BL,CL)≡(7,3) and those of D are (MD,OA+AM)≡4,7The coordinates of the vertex farthest from the origin are (4,7).