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The line intersects the curve if c=
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a
±1
b
±3
c
±5
d
±7
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Correct option is C
we have z=0 for the point, where the line intersects the curve. therefore x−23=y+12=0−1−1⇒x−23=1 and y+12=1⇒x=5 and y=1Putting these values in xy=c2, we get 5=c2⇒c=±5
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