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Questions  

The line x23=y+12=z11 intersects the curve xy=c2,z=0 if c=

a
±1
b
±3
c
±5
d
±7

detailed solution

Correct option is C

we have z=0 for the point, where the line intersects the curve. therefore x−23=y+12=0−1−1⇒x−23=1 and y+12=1⇒x=5 and y=1Putting these values in xy=c2, we get 5=c2⇒c=±5

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