The line x+33=y−2−2=z+11 and the plane 4x+5y+3z−5=0 intersect at a point

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(3,1,-2)

(3,-2,1)

(2,-1,3)

(-1,-2,-3)

answer is B.

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Detailed Solution

x+33=y−2−2=z+11=t ( say), the point (3t−3, 2−2t, t−1) subtute the given plane to get t

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