Q.
The line x+33=y−2−2=z+11 and the plane 4x+5y+3z−5=0 intersect at a point
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a
(3,1,-2)
b
(3,-2,1)
c
(2,-1,3)
d
(-1,-2,-3)
answer is B.
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Detailed Solution
x+33=y−2−2=z+11=t ( say), the point (3t−3, 2−2t, t−1) subtute the given plane to get t
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