Q.
The line y=mx bisects the area enclosed by lines x=0,y=0 and x=3/2 and the curve y=1+4x-x2. Then the value of m is
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a
136
b
132
c
135
d
137
answer is A.
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Detailed Solution
We have ∫03/21+4x−x2dx=2∫03/2mxdx⇒32+294−13278=m⋅94 On solving we get m=136
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