First slide

Pair of straight lines

Question

$The lines p (p^{2} + 1) x - y + q = 0 and {(p^{2} + 1)}^{2} x + (p^{2} + 1) y + 2 q = 0 are perpendicular to a common line for$

Moderate

A

exactly one value of p
B

no value of p
C

exactly two values of p
D

more than two values of p

Solution

Lines are parallel
$\Rightarrow \frac{p (p^{2} + 1)}{{(p^{2} + 1)}^{2}} = - \frac{1}{(p^{2} + 1)} \Rightarrow p = - 1 \Rightarrow p t a k e s e x a c t l y o n e v a l u e .$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App