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Lines $a x + b y + c = 0$ and $3 a + 2 b + 4 c = 0$ $a, b, c \in R$ are concurrent at the point.

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(3, 2)

(2, 4)

(3, 4)

(3/4, 1/2)

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detailed solution

Correct option is D

3a+2b+4c=0⇒ 34a+12b+c=0⇒ax+by+c passes through (3/4, 1/2) for all values of a, b, c.

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Lines ax + by + c = 0 and 3a + 2b + 4c = 0 a,b,c∈R are concurrent at the point.

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Lines $a x + b y + c = 0$ and $3 a + 2 b + 4 c = 0$ $a, b, c \in R$ are concurrent at the point.