Questions
The lines and are
diameters of a circle of area sq. units, then the equation of
the circle is
a
x2+y2+2x−2y−62=0
b
x2+y2+2x−2y−47=0
c
x2+y2−2x+2y−47=0
d
x2+y2−2x+2y−62=0
detailed solution
Correct option is C
The centre of the required circle lies at theintersection of 2x-3y-5=0 and 3x-4y-7=0. Thus, thecoordinates of the centre are (1, -1).Let r be the radius of the circle. Then, by hypothesis, we haveπr2=154⇒227r2=154⇒r=7Hence, the equation of the required circle is(x−1)2+(y+1)2=72⇒x2+y2−2x+2y−47=0Talk to our academic expert!
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