The lines x−y+z=1,3x−y−z+1=0 and x+4y−z=1,x+2y+z+1=0are
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a
Parallel
b
intersection
c
perpendicular and skew
d
non-perpendicular and skew
answer is D.
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Detailed Solution
The direction ratios of line of intersection of two planes x−y+z=1,3x−y−z+1=0are proportional to the vector ijk1−113−11=i0−j−2+k2The direction ratios of the line L1is0,1,1A point on the line P0,−1,0, by substituting z=0solve the simultaneous equations. The direction ratios of line of intersection of two planes x+4y−z=1,x+2y+z+1=0are proportional to the vector ijk14−1121=i6−j2+k−2The direction ratios of the line L2 is 3,−1,−1 A point on the line is Q−3,1,0, by substituting z=0solve the simultaneous equations.To check whether the lines lies in the same plane or not , find the value of x2−x1y2−y1z2−z1a1b1c1a2b2c2Hence, x2−x1y2−y1z2−z1a1b1c1a2b2c2= 00−21213−1−1=14, not equal to zero.Therefore, the lines are skew lines and not perpendicular.