The locus of the center of the circles such that the point (2,3) is the midpoint of the chord 5x +2y = 16 is
2x−5y+11=0
2x+5y−11=0
2x+5y+11=0
none of these
Slope of the given line =−52 ∴ −523+f2+g=−1 or 15+5f=4+2g Therefore, the locus is 2x−5y+11=0.