Locus of the centre of circle of radius 2 which rolls on out side the rim of the circle x2+y2−4x−6y−12=0 is

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x2+y2−4x−6y=0

x2+y2−4x−6y−36=0

x2+y2−4x−6y+3=0

x2+y2−4x−6y−25=0

answer is B.

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Detailed Solution

The locus of the centres is again a circle (outermost) concentric with the given circle C=(2,3)r1=4+9+12=5r2=5+2=7∴(x−2)2+(y−3)2=49 ⇒x2+y2−4x−6y−36=0

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