Q.
The locus of the centre of the circle which cuts the circles x2+y2+2g1x+2f1y+c1=0 and x2+y2+2g2x+2f2y+c2=0 orthogonally, is
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a
an ellipse
b
the radical axis of the given circles
c
a conic
d
another circle
answer is B.
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Detailed Solution
Let the circle be x2+y2+2gx+2fy+c=0This circle cuts the two given circles orthogonally∴ 2gg1+ff1=c+c1and 2gg2+ff2=c+c2Subtracting (ii) from (i), we get2gg1−g2+2ff1−f2=c1−c2.−2xg1−g2−2yf1−f2=c1−c2⇒ 2xg1−g2+2yf1−f2+c1−c2=0
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