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Questions  

The locus of the centre of a circle which touches externally the circle x2+y26x6y+14=0 and also touches the y-axis is given by the equation

a
x2−6x−10y+14=0
b
x2−10x−6y+14=0
c
y2−6x−10y+14=0
d
y2−10x−6y+14=0

detailed solution

Correct option is D

Let the centre of the circle be (h, k). Since the circle touches the axis of y. Therefore, radius.= h.The radius of the circle x2+y2−6x−6y+14=0 is 2 and it has its centre at (3, 3). It is given that the two circles touch each other externally∴   Distance between the centres = Sum of the radii⇒ (h−3)2+(k−3)2=h+2⇒ k2−10h-6k+14=0Hence, the locus of (h,k is y2−10x−6y+14=0.

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