Locus of the centroid of the triangle whose vertices are (acost,asint),(bsint,−bcost) and (1, 0); where t is a parameter is
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a
(3x−1)2+(3y)2=a2+b2
b
(3x+1)2+(3y)2=a2+b2
c
(3x+1)2+(3y)2=a2−b2
d
(3x−1)2+(3y)2=a2−b2
answer is A.
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Detailed Solution
If (h, k) is the centroid, thenh=acost+bsint+13k=asint−bcost+03⇒(3h−1)2+(3k)2=(acost+bsint)2+(asint−bcost)2Locus of =a2+b2(h,k) is (3x−1)2+(3y)2=a2+b2