Q.

The locus of image of the point λ2,2λ in the line mirror x−y+1=0 where λ is a parameter is

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a

4(y+1)=(x+1)2

b

4(y-1)=(x-1)2

c

4(y+1)=(x−1)2

d

4(y-1)=(x+1)2

answer is D.

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Detailed Solution

Image of λ2,2λ in the line mirror x−y+1=0 is h−λ21=k−2λ−1=−2λ2−2λ+12⇒h+1=2λ………… And k=λ2+1……… (2)  Putting value of λ from (1) into (2), we get k−1=h+122 locus is 4(y-1)=(x+1)2
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