The locus of the middle points of the normal chords of the rectangular hyperbola x2−y2=a2 is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
y2−x23=4a2x2y2
b
y2−x22=4a2x2y2
c
y2+x23=4a2x2y2
d
y2+x22=4a2x2y2
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Equation of the normal at (asec θ, atan θ) to the hyperbola x2−y2=a2 isaxsec θ+aytan θ=a2+a2=2a2 (1)Let (h, k) be the middle point of this normal then its equation ishx−ky−a2=h2−k2−a2 T=S1⇒ hx−ky=h2−k (2)Comparing (1) and (2) we gethsecθ=−ktanθ=h2−k22a⇒ secθ=h2−k22ah,tanθ=h2−k2−2ak So 1=sec2 θ−tan2 θ=h2−k224a21h2−1k2⇒ h2−k23+4a2h2k2=0 Locus of (h, k) is y2−x23=4a2x2y2