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Locus of the mid-point of the chord of the hyperbola x2a2-y2b2=1 which is a tangent to the circle x2+y2=c2  is

a
x2a2-y2b22=c2x2a4+y2b4
b
x2a2+y2b22=c2x2a4-y2b4
c
x2a2-y2b2=c2x2a2+y2b22
d
x2a4-y2b4=c2x2a2+y2b22

detailed solution

Correct option is A

Let (h, k) be the mid-point of the chord, then its equation ishxa2-kyb2=h2a2-k2b2Since it touches the circle x2+y2=c2h2a2-k2b2ha22+kb22=±c⇒h2a2-k2b22=c2h2a4+k2b4Required locus is x2a2-y2b22=c2x2a4+y2b4

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 If α+β=π then the chord joining the points α and β for  the hyperbola x2a2y2b2=1 passes through 


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