Locus of the mid-point of the chord of the hyperbola x2a2-y2b2=1 which is a tangent to the circle x2+y2=c2 is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
x2a2-y2b22=c2x2a4+y2b4
b
x2a2+y2b22=c2x2a4-y2b4
c
x2a2-y2b2=c2x2a2+y2b22
d
x2a4-y2b4=c2x2a2+y2b22
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Let (h, k) be the mid-point of the chord, then its equation ishxa2-kyb2=h2a2-k2b2Since it touches the circle x2+y2=c2h2a2-k2b2ha22+kb22=±c⇒h2a2-k2b22=c2h2a4+k2b4Required locus is x2a2-y2b22=c2x2a4+y2b4