The locus of the midpoints of the chord of the circle, x2+y2=25 which is tangent to the hyperbola, x29-y216=1 is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
x2+y22−16x2+9y2=0
b
x2+y22−9x2−16y2=0
c
x2+y22−9x2+144y2=0
d
x2+y22−9x2+16y2=0
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Equation of the chord having mid point h,k to the circle x2+y2=25 is hx+ky=h2+k2it can be written as y=−hkx+h2+k2kGiven this is tangent to the hyperbola x29−y216=1c2=a2m2-b2⇒h2+k2k2=9h2k2−16⇒h2+k22=9h2−16k2The locus is x2+y22=9x2-16y2 or x2+y22-9x2+16y2=0