Download the app

Questions  

 The locus of the midpoints of the chord of the circle, x2+y2=25 which is tangent to the  hyperbola, x29-y216=1 is 

a
x2+y22−16x2+9y2=0
b
x2+y22−9x2−16y2=0
c
x2+y22−9x2+144y2=0
d
x2+y22−9x2+16y2=0

detailed solution

Correct option is D

Equation of the chord having mid point h,k to the circle x2+y2=25 is hx+ky=h2+k2it can be written as y=−hkx+h2+k2kGiven this is tangent to the hyperbola x29−y216=1c2=a2m2-b2⇒h2+k2k2=9h2k2−16⇒h2+k22=9h2−16k2The locus is x2+y22=9x2-16y2   or    x2+y22-9x2+16y2=0

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

If the chords of contacts of the tangents from the points

x1, y1 and x2, y2 to the hyperbola 2x23y2=6

are at right angle, then 4x1x2+9y1y2 is equal to


phone icon
whats app icon