The locus of a point that is equidistant from the lines $$x+y$$−$$22=0$$ and $$x+y$$−$$2=0$$ is

Correct option is 32x+2y−32=0

Questions

The locus of a point that is equidistant from the lines $x + y - 2 \sqrt{2} = 0 and x + y - \sqrt{2} = 0 is$

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x+y−52=0

x+y−32=0

2x+2y−32=0

2x+2y−52=0

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detailed solution

Correct option is C

For any point P(x, y) that is equidistant from the given line, given lines are parallel , so the required line is ax+by+ c1+c22=0 ⇒x+y+-22-22=0⇒2x+2y-32=0

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The locus of a point that is equidistant from the lines x+y−22=0 and x+y−2=0 is

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The locus of a point that is equidistant from the lines $x + y - 2 \sqrt{2} = 0 and x + y - \sqrt{2} = 0 is$