The locus of the point from which the length of the tangent to the circle x2+y2−2x−4y+4=0 is 3 units is

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x2+y2−2x−4y−9=0

x2+y2−2x−4y−4=0

x2+y2−2x−4y−3=0

x2+y2−2x−4y−5=0

answer is D.

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Detailed Solution

length of the tangent from x1,y1 to the circle x2+y2−2x−4y+4=0 is s11=3 ⇒locus of x1,y1 is x2+y2−2x−4y+4=9 ⇒x2+y2−2x−4y-5=0

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