The Locus of the point of intersection of two lines x secα +y tanα=a; x tanα+ y secα=b then

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x2−y2=a2−b2

x2+y2=a2+b2

x2−y2=a2+b2

x2+y2=a2−b2

answer is A.

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Detailed Solution

The locus of the P. O.I of two lines , xsecα+yTanα=a ,xTanα+ysecα=b squaring (and) subtracting ⇒ x2sec2α- tan2α -y2sec2α-tan2α =a2-b2 x2−y2=a2−b2

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