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The locus of the point P such that $P A^{2} + P B^{2} = 10$ where $A = (2, 3, 4), B = (3, - 4, 2)$ is

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x2+y2+z2−x+y−4z+12=0

x2+y2+z2−5x+y−6z+24=0

2(x2+y2+z2)−x+y−4z+12=0

x2+y2+z2+x−y+4z−12=0

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detailed solution

Correct option is B

P=(x,y,z)using distance formula in given equation

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The locus of the point P such that PA2+PB2=10 where A=(2,3,4),B=(3,−4,2) is

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The locus of the point P such that $P A^{2} + P B^{2} = 10$ where $A = (2, 3, 4), B = (3, - 4, 2)$ is