Questions

The locus of the point P such that $P{A}^{2}+P{B}^{2}=10$ where $A=(2,3,4),B=(3,-4,2)$ is

a

x2+y2+z2−x+y−4z+12=0

b

x2+y2+z2−5x+y−6z+24=0

c

2(x2+y2+z2)−x+y−4z+12=0

d

x2+y2+z2+x−y+4z−12=0

detailed solution

Correct option is B

P=(x,y,z)using distance formula in given equation

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The equation of motion of a point in space is $x=2t,\text{\hspace{0.17em}}y=-4t,z=4t,$ where ‘t’ is measured in hours and the coordinates of moving point in kilometers. The distance of the point from the starting point O (0,0,0) at the end of 10hours is

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