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Q.

The locus of the point P such that PA2+PB2=10 where A=(2,3,4),B=(3,−4,2) is

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a

x2+y2+z2−x+y−4z+12=0

b

x2+y2+z2−5x+y−6z+24=0

c

2(x2+y2+z2)−x+y−4z+12=0

d

x2+y2+z2+x−y+4z−12=0

answer is B.

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Detailed Solution

P=(x,y,z)using distance formula in given equation
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