Q.
The locus of the point (rsecαcosβ,rsecαsinβ,rtanα) is
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a
x2+y2−z2=r2
b
x2+y2+z2=r2
c
x2+y2−z2=2r2
d
x2−y2+z2=r2
answer is A.
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Detailed Solution
We have x2+y2-z2=r2sec2αcos2β+r2sec2αsin2β-r2tan2α =r2
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