The locus of a point represented by $$x=a2t+1t$$, $$y=a2t$$−$$1t$$, is

Correct option is 4none of these

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The locus of a point represented by $x = \frac{a}{2} (\frac{t + 1}{t}), y = \frac{a}{2} (\frac{t - 1}{t}),$ is

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Correct option is D

We have,x=a2t+1t,y=a2t−1t⇒ 2xa=1+1t,2ya=1−1t⇒ 2xa−1=1t,1−2ya=1t⇒ 2xa−1=1−2ya⇒x+y=ar which is a straight me.

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The locus of a point represented by x=a2t+1t, y=a2t−1t, is

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The locus of a point represented by $x = \frac{a}{2} (\frac{t + 1}{t}), y = \frac{a}{2} (\frac{t - 1}{t}),$ is