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The locus of the point which moves in a plane so that the sum of the squares of its distances from the lines $a x + b y + c = 0$ and $b x - a y + d = 0$ is $r^{2},$ is a circle of radius.

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r(a2+b2)

ra2−b2

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Correct option is B

The given lines are perpendicular. So shifting the origin to their point of intersection if (h, k) are the new coordinates of any point on the locus then h2+k2=r2 and the locus is x2+y2=r2 which is a circle of radius r.

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The locus of the point which moves in a plane so that the sum of the squares of its distances from the lines ax+by+c=0 and bx−ay+d=0 is r2, is a circle of radius.

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The locus of the point which moves in a plane so that the sum of the squares of its distances from the lines $a x + b y + c = 0$ and $b x - a y + d = 0$ is $r^{2},$ is a circle of radius.