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$7 \log (\frac{16}{15}) + 5 \log (\frac{25}{24}) + 3 \log (\frac{81}{80})$ is equal to

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Correct option is C

Given expression =log167157.255245.813803=log 2.

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7 log1615+5 log2524+3 log8180 is equal to

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$7 \log (\frac{16}{15}) + 5 \log (\frac{25}{24}) + 3 \log (\frac{81}{80})$ is equal to