First slide

Introduction to real valued functions

Question

$7 \log (\frac{16}{15}) + 5 \log (\frac{25}{24}) + 3 \log (\frac{81}{80})$ is equal to

Moderate

A

0
B

1
C

$\log 2$
D

$\log 3$

Solution

Given expression $= \log (\frac{16^{7}}{15^{7}} . \frac{25^{5}}{24^{5}} . \frac{81^{3}}{80^{3}}) = \log 2 .$

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